反向传导算法

From Ufldl

Jump to: navigation, search
Line 156: Line 156:
:<math>
:<math>
= \delta^{(n_l)}_i\cdot\frac{\partial z^{n_l}_i}{\partial z^{n_{l-1}}_i} = \delta^{(n_l)}_i\cdot\frac{\partial}{\partial z^{n_{l-1}}_i}\sum_{j=1}^{s_{l-1}} W^{n_l-1}_{ji} f(z^{n_l-1}_i)
= \delta^{(n_l)}_i\cdot\frac{\partial z^{n_l}_i}{\partial z^{n_{l-1}}_i} = \delta^{(n_l)}_i\cdot\frac{\partial}{\partial z^{n_{l-1}}_i}\sum_{j=1}^{s_{l-1}} W^{n_l-1}_{ji} f(z^{n_l-1}_i)
-
= \left( \sum_{j=1}^{s_{l-1}} W^{n_l-1}_{ji} \delta^{(n_l)}_i \right) f(z^{n_l-1}_i)
+
= \left( \sum_{j=1}^{s_{l-1}} W^{n_l-1}_{ji} \delta^{(n_l)}_i \right) f'(z^{n_l-1}_i)
</math>
</math>
-
根据递推过程,将n_l-1与n_l的关系替换为l与l+1的关系,可以得到原作者的结果:
+
根据递推过程,将<math>n_l-1<\math>与<math>n_l<\math>的关系替换为l与l+1的关系,可以得到原作者的结果:
::<math>
::<math>
                 \delta^{(l)}_i = \left( \sum_{j=1}^{s_{l+1}} W^{(l)}_{ji} \delta^{(l+1)}_j \right) f'(z^{(l)}_i)
                 \delta^{(l)}_i = \left( \sum_{j=1}^{s_{l+1}} W^{(l)}_{ji} \delta^{(l+1)}_j \right) f'(z^{(l)}_i)

Revision as of 17:20, 7 March 2013

Personal tools